每日一题：隐藏个人信息 - 刷题题解

给你一条个人信息字符串 s ，可能表示一个邮箱地址，也可能表示一串电话号码。

题目链接：https://leetcode.cn/problems/masking-personal-information

直接按题意模拟，分别处理电话号码和邮箱即可。

	class Solution {
	public String maskPII(String s) {
	int at = s.indexOf('@');
	if (at != -1) {
	// 是邮箱
	if (at > 0) {
	char first = Character.toLowerCase(s.charAt(0));
	char last = Character.toLowerCase(s.charAt(at - 1));
	String domain = s.substring(at + 1).toLowerCase();
	return String.format("%c*****%c@%s", first, last, domain);
	} else {
	return "";
	}
	} else {
	// 是电话号码
	char[] chs = s.toCharArray();
	int k = 0;
	for (int i = 0; i < chs.length; ++i) {
	if (chs[i] >= '0' && chs[i] <= '9') {
	chs[k++] = chs[i];
	}
	}

	if (k < 10) return "";

	String ph = new String(chs, k - 4, 4);
	if (k == 10) {
	return String.format("*-*-%s", ph);
	} else {
	StringBuilder sb = new StringBuilder();
	while (k > 10) {
	sb.append('*');
	--k;
	}
	return String.format("+%s-*-*-%s", sb.toString(), ph);
	}
	}
	}
	}

	class Solution {
	public String maskPII(String s) {
	int at = s.indexOf('@');
	if (at != -1) {
	// 是邮箱
	if (at > 0) {
	StringBuilder ret = new StringBuilder();
	ret.append(Character.toLowerCase(s.charAt(0)))
	.append("*****")
	.append(Character.toLowerCase(s.charAt(at - 1)))
	.append(s.substring(at).toLowerCase());
	return ret.toString();
	} else {
	return "";
	}
	} else {
	// 是电话号码
	char[] chs = s.toCharArray();
	int k = 0;
	for (int i = 0; i < chs.length; ++i) {
	if (chs[i] >= '0' && chs[i] <= '9') {
	chs[k++] = chs[i];
	}
	}

	if (k < 10) return "";
	StringBuilder sb = new StringBuilder();
	String ph = new String(chs, k - 4, 4);
	if (k == 10) {
	sb.append("*-*-").append(ph);
	} else {
	sb.append('+');
	while (k > 10) {
	sb.append('*');
	--k;
	}
	sb.append("-*-*-").append(ph);
	}

	return sb.toString();
	}
	}
	}